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The National Testing Agency (NTA) has released the provisional answer key of the Joint Central Scientific and Industrial Research- University Grants Commission National Eligibility Test (JOINT CSIR-UGC NET) exam. This exam was conducted on 25, 26 and 27 July 2024. The agency has also released the question paper and response sheet along with the provisional answer key. Apart from this, objection windows have also been opened for the students. To check the answer key, candidates have to visit the official website csirnet.nta.ac.in.
How can candidates check CSIR-UGC NET July answer key-
1. First of all you have to visit the official website csirnet.nta.ac.in.
2. Now you have to click on the link CSIR-UGC NET Answer Key 2024 given on the home page.
3. After this you will have to log in.
4. After this you have to click on submit.
5. Now a new window will open in front of you and the answer key will appear on your screen.
6. Now you carefully check the answer key PDF.
7. Now you can download the CSIR-UGC NET answer key PDF.
Check the answer key from this link
Let the candidates know that the objection window of CSIR-UGC NET will be open from 9 August to 11 August 2024. Candidates will have to pay a non-refundable fee of Rs 200 to register an objection on each question. The last date to pay the fee is 11 August 2024 at 11:50 pm. If the candidates feel that the answer to the question given in the answer key is wrong, then they can register their objection by going to the objection window. The objection filed by the candidates will be checked by a panel of subject experts. The final answer key will be prepared as per the opinion of the subject experts and the result will be prepared on that basis.
